Question

How much NaCl would be required to prepare normal saline(0.9% NaCl) in a 250 ml volumetric flask?​

Answer 1

Answer:

To make the solution we need to calculate the amount of NaCl to dissolve to make 250 mL of solution. The solution is made by adding 4.38 g NaCl to a 250-mL volumetric flask. About 100 mL of water are added and when all the NaCl dissolves water is added up to the line on the volumetric flask.

Explanation:

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Answer 2

Answer: 2.25 g Of NaCl would be required  to prepare normal saline(0.9% NaCl) in a 250 ml volumetric flask.

Explanation:

• The concentration of a solution can be expressed using a variety of concentration words. Molarity, morality, mass concentration, mass/mass concentration, etc. are a few of them. The density of the solution is another name for the mass concentration. It can be said to be g/mL, g/L, kg/L and kg/m³.
• Solution is a combination of solute and solvent. A higher mass concentration indicates that there is a greater concentration of solute in the solution.

We can find the solution using two methods:

a) Mass/volume ratio of 0.9% m/V

250 mL x 0.9% m/V is equal to 250 mL x 0.009 g/mL, or 2.25 g.

b) The solution has a density of 0.9%m/m, which equals 1 mass of the solution (DV = m) and a mass of 250 G

⇒ 0.009 = X/250

⇒ X = 2.25 g

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