How much NH3 would be produced if 100g of N2 reacts completely with H2?
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N2 + 3H2 ----> 2NH3
1 MOL OF N2 GIVES 2 MOLES OF NH3
100÷28 MOLES OF Ñ2 GIVES 2 ×100÷28=7.14g of ammonia
1 MOL OF N2 GIVES 2 MOLES OF NH3
100÷28 MOLES OF Ñ2 GIVES 2 ×100÷28=7.14g of ammonia
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