Math, asked by balaramakrishnan7, 6 months ago

How much of high-grade coal priced at INR 600/kg should be mixed with 200 kg of ordinary coal, priced at INR 450/kg, so as to make a profit of 10%, by selling the
mixture at INR 550/kg?

Options
85 kg
250 kg
175 kg
100 kg​

Answers

Answered by fatesingh9250240975
15

Answer:

250 is correct answer check

Answered by marishthangaraj
0

100 kg of high-grade coal should be mixed with 200 kg of ordinary coal, to make a profit of 10%, by selling the mixture at INR 550/kg

Given:

High-grade coal priced at INR 600/kg

Ordinary coal, priced at INR 450/kg,

The seller made a profit of 10% by selling the mixture at INR 550/kg

To find:

How much of high-grade coal should be mixed with 200 kg of ordinary coal, to make a profit of 10%, by selling the mixture at INR 550/kg

Solution:

Step 1 of 2:

Let, 'x' kgs of high grade coal required to be mixed with 200 kg of ordinary coal.

High-grade coal priced at INR 600/kg

Cost of  high grade coal = 600x

Ordinary coal, priced at INR 450/kg,

Cost of  ordinary coal = 450 × 200

Cost of  ordinary coal = INR 90000

Total cost = 600x + 90000

Step 2 of 2:

The seller made a profit of 10% by selling the mixture at INR 550/kg

Selling price after 10% gain = (1+\frac{10}{100}) × ( 600x + 90000 )

Selling price after 10% gain = 1.1 × ( 600x + 90000 )

Actual selling price = 550 × ( x + 200 )

Therefore,

550 × ( x + 200 ) =  1.1 × ( 600x + 90000 )

550x + 110000= 660x + 99000

110000 - 99000 = 660x - 550x

11000 = 110x

x = \frac{11000}{110}

x = 100 kg

Therefore,

100 kg of high-grade coal should be mixed with 200 kg of ordinary coal, to make a profit of 10%, by selling the mixture at INR 550/kg

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