How much of liquid at 200°C must be added to 50g of same liquid at 20°C so that temperature becomes 70°C
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I think answer will be 72g by the given below formula. T3=M1S1T1+M2S2T2/T1+T2 where,, T3= resultant temp,, S1 and S2 are specific heats M1andM2 are mass
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