How much of naoh is required to neutralise 1500 cm3 of 0.1n hcl?
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Answered by
99
Weight of NaOH = N* E.W. * V/1000
Put the values in the above formula
Weight of NaOH required.= 0.1 *40 *1500/1000
= 6 gm
Hope it helps you
Put the values in the above formula
Weight of NaOH required.= 0.1 *40 *1500/1000
= 6 gm
Hope it helps you
Answered by
65
I hope this will help you
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