How much of NaOH is required to neutralize 1500 cm3 of 0.1 HCL
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Answer:Solution:
1500 of 0.1 N HCl 1500 of 0.1 N NaOH
1500 of 0.1 M NaOH
= = 0.15 mol.
= 0.15 mol 40 g mol = 6 g
Explanation:
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Answer:
sorry i can't understand this questions
Explanation:
I am so so so soory
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