how much of NaOH is required to neutralize 1500CC of 0.1(N) HCL?
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2
150 m.eq. of NaOH is required
amartya:
HOW?
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0
apply N1V1 = N2V2
N1V1 = ? , N2 = 0.1 , V2 = 1500cc
N1V1 = 0.1*1500
N1V1 = 150milieqv.
N1V1 = ? , N2 = 0.1 , V2 = 1500cc
N1V1 = 0.1*1500
N1V1 = 150milieqv.
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