Question

How much of NaOH is required to neutralize 1500cm^3of 0. 1 N HCL

Answer 1

Since n factor of HCL is 1 hence Normality = Molarity  Moles of HCL=Moles of NaOH  For complete neuralisation  Hence,0.1M×volume in litre  0.1×15×10^(-7) =1.5×10^(-7)moles