How much of water has to be added to dilute 100 mL of 0.3M solution into 0.2M
solution?
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Answer:
Molarity = n/ v ( solution )
M1 = n / V1 ( solution ) -------1
M2 = n/ V2 ( solution ) ---------2
from 1 and 2 ..
M1 / M2 = V2 / V1
substituting the values,
V2 = 2 m × 100 ml / 0.5 m
V2 = 400 ml
Hence , V2 - V1 = 400 - 100 ml = 300 ml
therefore, 300 ml is added to the solution.
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