How much oxygen will a closed class room of length breadth and height 10m 8m and 5m respectively contain? ( air contains 21% of oxygen )
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Answer:
84m^2
Step-by-step explanation:
l= 10m
b= 8m
h= 5m
volume= lbh = 10 x 8 x 5 = 400m^2
% of oxygen = 21%
amount of oxygen = 21% of v = 21/100 x 400
= 84m^2
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