Question

how much pcl5 must be taken in 9.2L vessel to get 0.5 mol Cl2 at given temperature. Kc=0.0414​

Answer 1

Explanation:

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Answer 2

Answer:

Since the total volume is 1 L, the number of moles is equal to molar concentration.

Let x mole of PCl

5

is added. The equilibrium concentration of PCl

5

is x−0.1 M as 0.1 mole of PCl

5

will react to give 0.1 mole of PCl

3

and 0.1 mole of Cl

2

at equilibrium.

K

c

=

[PCl

5

]

[PCl

3

][Cl

2

]

0.0414mol/L=

(x−0.1)mol/L

0.1mol/L×0.1mol/L

0.0414(x−0.1)=0.01

0.0414x−0.00414=0.01

0.0414x=0.01414

x=0.341