How much PCl5 should be heated to obtain 7.1g Cl2 and 13.75g PCl3 , if law of conservation of mass is true ?
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Answers
pcl5------>pcl3 +cl2
208.5g 137.5g 71g
moles of pcl3 and cl2 to be produced =0.1
as 7.1/71=0.1
and 13.75/1375=0.1
as co effiecient is 1..therefore 1 mole pcl5 decomposes to 1 mole pcl3 and 1 mole cl2
But here 0.1 mole of cl2 is produced
therfore 0.1 mole of pcl5 is required
0.1 mole pcl5= 208.5x0.1=20.85g
Verification 20.85=7.1+13.75
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Answer:
✨pcl5------>pcl3 +cl2
208.5g 137.5g 71g
✨ moles of pcl3 and cl2 to be produced =0.1
⏩as 7.1/71=0.1
⏩and 13.75/1375=0.1
✔as co effiecient is 1..therefore 1 mole pcl5 decomposes to 1 mole pcl3 and 1 mole cl2
❇But here 0.1 mole of cl2 is produced
✳therfore 0.1 mole of pcl5 is required
✅0.1 mole pcl5= 208.5x0.1=20.85g
➡Verification 20.85=7.1+13.75