how much percentage change in acceleration due to gravity on an object if object is initially at 2R distance above the surface of the earth and falls through R distance
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If object is at 2R distance above the Earth's surface then,
g'=g(R/2R+R)=g/3
New g when object is at R distance
=>g''=g(R/R+R)=g/2
%change={(g/3-g/2)/g×1/3}×100
=(g/6)/(g/3)×100 = 50% Ans.
Anonymous:
Please if you know then tell me that my answer is correct or not.
well ,it is not the correct answer but the should be any one of these
a) decrease by 300%
b) increase by 300%
c) decrease by 125%
d) increase by 125%
these are four options
As the height decrease the g increases so 2R->R then g increases. Then (a) and (d) must be there. But I am confused that with respect to which the answer should be there.
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you
Explanation:
first you have to your girl friend 20 time an
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