How much positive and negative charge is present in 1 g of water how many electrons are present in eight molecular mass of water is 18 g
Answers
Answer:
Answer
Let us consider that one cup of has 250 ml of water
Density of water is 1 g/cc in cgs system
Therefore the mass of one cup of water =250 g
Molecular weight of water =18 g
Number of moles of water in 250gram=
18
250
=13.888moles
We know that one mole=6.02×10
23
molecules.
The number of molecules in one cup of water=13.888×6.02×10
23
=8.36×10
24
molecules.
1 molecule of water=2hydrogen(2 protons)+1oxygen(8 protons)
Total protons in one water molecule=10=Total number of electrons.
Total positive and negative charge has the same magnitude.
We know charge of proton=1.6×10
−19
C
Total positive charge in 250g of water in cup=10×8.36×10
24
×1.6×10
−19
=1.338×10
7
C
So i one cup of water (250ml) there are 1.338×10
7
C positive charge and −1.338×10
7
C negative charge
Totally they will be neutral
Explanation:
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