How much positive and negative charge is there in a cup of water ???
Answers
Given a cup of water
We need to find the charge present in that cup
Let us assume that the cup is of 250g or 250 mL
We know that the molecular mass of water is 18g/ mol
Each molecule of water contains 2+8=10 electrons and protons.
So let the number of molecules present in a cup of water = n
=6.022×1023×250/18 =8.36×1024
Therefore,
Total number of electrons or protons present in a cup of water be N
=n×10
=8.36×1025
Total negative or positive charge is given by
q=N e
=8.36×1025×1.6×10-19 C
=1.33×107 C
So the number of charges present in a 250g cup = 1.33×107 C
Hope it helps you :)
Answer:
Given a cup of water
We need to find the charge present in that cup
Let us assume that the cup is of 250g or 250 mL
We know that the molecular mass of water is 18g/ mol
Each molecule of water contains 2+8=10 electrons and protons.
So let the number of molecules present in a cup of water = n
=6.022×1023×250/18 =8.36×1024
Therefore
Total number of electrons or protons present in a cup of water be N
=n×10=8.36×1025
Total negative or positive charge is given by
q=N e
=8.36×1025×1.6×10-19 C
=1.33×107 C
So the number of charges present in a 250g cup ==1.33×107 C
Explanation:
I hope it will help u