Question

how much potassium chlorate should be heated to produce 2.24 litre of oxygen ato NTP

Answer 1

Explanation:

The balanced chemical equation for the reaction is:

2 KClO3(s) → 3 O2(g) + 2 KCl(s)

Molar mass of KClO3 = 39+35.5+16x3 = 122.5

Molar gas volume at STP = 22.4 litres

From the equation, 2 moles of KClO3 produce 3 moles of O2

⇒ 2 moles of KClO3 produce 3x22.4 litres of O2

22.4 L of O2 will be produced from = (22.4 x 2)/3x22.4

                                                           = 2/3  moles of KClO3

Mass of KClO3 = 2/3 x 122.5

                         = 81.67g