how much potassium chlorate would dissolve in 200g water at 20c grade 7
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Given that the solubility of sodium chloride is 36 grams per 100 grams of water. Which of the following solutions would be considered supersaturated? A. dissolve 5.8 moles of NaCl in 1 L of water B. dissolve 1.85 moles of NaCl in 300 ml of water C.
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The answer is 61.275
GIVEN
Mass of water = 200 grams
TO FIND
The solubility of potassium chlorate at 20°C
SOLUTION
The above problem can be simply solved as follows;
Solubility of a substance = (Mass of solute/mass of solvent) × 100
Mass of potassium cholrate = 122.55 g/mol
Solubility = (122.55/200) × 100
= 61.275
Hence, The answer is 61.275
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