how much potential energy is lost by 5 kg object to the kinetic energy due to increase in height of 4.5 metre.
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Although Kinetic Energy = 1/2 * m * v^2, you don't have to calculate the velocity directly to solve this problem.
The potential energy of an item is: m*g*h
m is mass in kg.
g is the acceleration due to gravity in m/s^2 (e.g. 9.81)
h is the height in meters
This yields 10*9.81*20 = 1962 kg*m^2/sec^2 (aka N*m or joules)
immediately before impact, 100 % of the potential energy has been converted to kinetic energy.
1962 Joules is my final answer.
The potential energy of an item is: m*g*h
m is mass in kg.
g is the acceleration due to gravity in m/s^2 (e.g. 9.81)
h is the height in meters
This yields 10*9.81*20 = 1962 kg*m^2/sec^2 (aka N*m or joules)
immediately before impact, 100 % of the potential energy has been converted to kinetic energy.
1962 Joules is my final answer.
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