How much power is needed to drive two times faster?
Answers
Answered by
2
HEYA!!
the answer is =The relationship between power and speed for land vehicles is not, unfortunately, linear. That is to say, that if you double the power you do not manage to double the speed.
At any speed above somewhere around 40 km/h (25 mph) on a flat and smooth road, aerodynamic drag of the vehicle becomes the most important force that prevents the vehicle from going faster. For high speeds, let's say above 160 km/h (100 mph), aerodynamic drag of a typical car is so high that it can be considered the only force acting on a road vehicle, all the others being irrelevant compared to it (despite also all other friction forces having increased as speed has increased).
^_^
Answered by
0
The first semester of an undergraduate physics course invariably spends a lot of time on two big ideas: The momentum principle and the work energy principle. Both deal with forces acting on an object, which often leads students to think they are similar. In a way, they are, and they play a huge role in almost everything you learn during an introduction to physics.
Before I give you a great physics question that uses these ideas, I will go over them in a super-brief physics lesson. First, the momentum principle says that a net force changes the momentum of an object where the momentum is the product of mass and velocity. Working in one dimension to avoid dealing with vectors, I can write it like.
If you consult your introductory physics textbook, you'll see that this is essentially the same as Newton's Second Law, which states that the net force is equal to the product of mass and acceleration (where acceleration represents the change in velocity). You can rewrite the momentum principle to solve for the change in momentum (which is useful). It looks like this
Before I give you a great physics question that uses these ideas, I will go over them in a super-brief physics lesson. First, the momentum principle says that a net force changes the momentum of an object where the momentum is the product of mass and velocity. Working in one dimension to avoid dealing with vectors, I can write it like.
If you consult your introductory physics textbook, you'll see that this is essentially the same as Newton's Second Law, which states that the net force is equal to the product of mass and acceleration (where acceleration represents the change in velocity). You can rewrite the momentum principle to solve for the change in momentum (which is useful). It looks like this
Similar questions