Question

how much pressure is applied on a girl of 40 Kg if she is standing on her both feet and area under her one feet is 8 cm square ?​

Answer 1

Answer:

Pressure= weight/area

Weight = 40 kg × 10 m/s^2

Area = 8 cm sq

= 8×10^-4 m sq

hence,

P = 400× 10000/8

= 50×10^4 Pa