Question

How much pressure will be felt by a gas balloon which at 100m depth in a sea from sea level?

Answer 1

P₀ = pressure at the top = atmospheric pressure = 1.01325 x 10⁵ Pa

ρ = density of water = 1000 kgm⁻³

g = acceleration due to gravity = 9.8 ms⁻²

P = pressure at the bottom experienced by the gas balloon

h = depth of the gas balloon from sea level = 100 m

Pressure at the bottom is given as

P = P₀ + ρ gh

inserting the above values in the above equation

P = ( 1.01325 x 10⁵) + (1000) (9.8) (100)

P = 1081325 Pa

Answer 2

Answer:p=1081325pa

Explanation:

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