How much pure alcohol added to 500 ml of a 16% solution to make its strength 30% ?
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Let pure alcohol added be x ml.
Alcohol at first =16% of 500 ml
=80 ml
A/q,
80+x/500+x=30/100
30(500+x)=100(80+x)
15000+30x=8000+100x
100x-30x=15000-8000
70x=7000
x=100
Alcohol at first =16% of 500 ml
=80 ml
A/q,
80+x/500+x=30/100
30(500+x)=100(80+x)
15000+30x=8000+100x
100x-30x=15000-8000
70x=7000
x=100
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