how much pure alcohol be added to 400 ml of a 15% solution to make its strength 32%?
Answers
Answered by
7
400ml has 15% alcohol i.e 60ml . This means we have 340ml of water or the liquid with which alcohol is mixed
Let V be the volume of alcohol added to make the strength 32%
then V/340+V = 32/100. solving this we get V as 160ml
so we need to add 160 -60 = 100ml of alcohol
Let V be the volume of alcohol added to make the strength 32%
then V/340+V = 32/100. solving this we get V as 160ml
so we need to add 160 -60 = 100ml of alcohol
sanjit52:
I cant understand this term V/340+V= 32/100
Let the required number of milliliters of pure alcohol be x ml Given 15% of 400 ml shd be added with 100% pure alcoholHence 400(15%) + x(100%) = (400+x)(32%)
solve by this statement
Answered by
7
let xml is added
15% of 400=60 ml
after addition
(60+x)/(400+x)=32%
solving x=100 ml
15% of 400=60 ml
after addition
(60+x)/(400+x)=32%
solving x=100 ml
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