Question

How much pure alcohol has to be added to 400
ml of a soluation containing 15% of alcohol to
change the concentration of alcohol in the
mixture to 32%?​

Answer 1

Answer:

100ml

Step-by-step explanation:

15% OF 400=60 ml OF ALCOHOL

LET X ml IS BEING ADDED , THEREFORE TOTAL ALCOHOL=60+X ml

NEW TOTAL VOLUME =400+X ml

A.T.Q WE GET:-

32%(400+X)=60+X

ON SOLVING THIS X COMES OUT TO BE 100ml

Answer 2

Hi mate,

Solution :

=> Volume of alcohol in 400 ml solution

➾ 0.15 × 400 ml

=> Volume of alcohol in 400 ml solution

➾ 60 ml

=> Volume of others liquid

➾ 340 ml

=> Let x ml of alcohol is added to make it 32% strong

=> Then, volume of alcohol

➾ 60+x ml

=> Volume of other liquid

➾ 340 ml

=> Volume of solution

➾ 400 + x ml

➾ 0.32 × (400 + x) = 60 + x

➾ 128 + 0.32x = 60 + x

➾ 0.68x = 68

➾ 68x = 6800

➾ x = 100 ml ...

Answer : 100 ml pure alcohol must be added to 400ml of a 15% solution to make it's strength 32%

i hope it helps you