Question

how much pure alcohol is to be added in 300mlof 20%solution to make 40%​

Answer 1

Answer:

20 % will be added

I hope it helps you

Answer 2

Answer:

100ml

Step-by-step explanation:

Given,

Solution = 300ml

Strength = 40%

Let's take x value of alcohol be added

We have to calculate the quantity of alcohol by using formula for quantity:

Quantity of alcohol in 300ml solution

Q = 20 by x 300

100

Q = 60ml

after that, we need to calculate the value of x by using formula for strength

60 + 100 by 40 by

__________ = ____ (therefore cross multiply it)

300 +100 100

100(60 + x) = 40(300 + x) or you can take like this also 60 + x(100) = 300 + x(40) this two have no difference if you write this also the answer will be same or correct

so, 100(60 + x) = 40(300 + x)

6000 + 100x = 12,000 + 40x

100x - 40x = 12,000 - 6000

60x = 6000

x = 6000 by (First, you cancel the zero and then

60 cut both the numbers by taking 6

so, the answer will be 100ml)

x = 100ml

therefore, hence 100ml must be added in pure alcohol