Question

how much pure alcohol must be added to 400 ml of a 15% solution to make its strength 32%.
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Answer 1

Answer:

Step-by-step explanation:

Answer: 100 ml of pure alcohol must be added to 400 ml of a 15% solution.

Step-by-step explanation:

Since we have given that

Quantity of solution = 400 ml

Let quantity of pure alcohol be 'x'.

According to question,

So, we will solve it for the value of 'x':

Hence, 100 ml of pure alcohol must be added to 400 ml of a 15% solution

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Answer 2

Hi mate,

Solution :

=> Volume of alcohol in 400 ml solution

➾ 0.15 × 400 ml

=> Volume of alcohol in 400 ml solution

➾ 60 ml

=> Volume of others liquid

➾ 340 ml

=> Let x ml of alcohol is added to make it 32% strong

=> Then, volume of alcohol

➾ 60+x ml

=> Volume of other liquid

➾ 340 ml

=> Volume of solution

➾ 400 + x ml

➾ 0.32 × (400 + x) = 60 + x

➾ 128 + 0.32x = 60 + x

➾ 0.68x = 68

➾ 68x = 6800

➾ x = 100 ml ...

Answer : 100 ml pure alcohol must be added to 400ml of a 15% solution to make it's strength 32%

i hope it helps you