Question

how much pure alcohol must be added to 400ml of a 15% solution to make its strength 32% ​

Answer 1

Answer:

Answer:Since we have given that

Answer:Since we have given thatQuantity of solution = 400 ml

Answer:Since we have given thatQuantity of solution = 400 mlLet quantity of pure alcohol be 'x'.

Answer:Since we have given thatQuantity of solution = 400 mlLet quantity of pure alcohol be 'x'.According to question,

Answer:Since we have given thatQuantity of solution = 400 mlLet quantity of pure alcohol be 'x'.According to question,So, we will solve it for the value of 'x':

Answer:Since we have given thatQuantity of solution = 400 mlLet quantity of pure alcohol be 'x'.According to question,So, we will solve it for the value of 'x':Hence, 100 ml of pure alcohol must be added to 400 ml of a 15% solution.

Answer 2

Answer:

Volume of alcohol should be added to make strength 32% is 100 ml

Step-by-step explanation:

400 ml solution has strength of 15 %

this means that it has 60 ml of alcohol

let amount of alcohol added be x

so the equation will be

        x+60   ×  100 = 32

       400+x

On solving this equation we get x = 100 ml

So 100 ml of alcohol should be  added to 400 ml solution to make strength 32%.

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