How much pure alcohol should be added to 600ml ,15% alcohol solution to make it contain 25% alcohol?
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Answer:
80 ml
Step-by-step explanation:
Let +x+ = ml of pure alcohol to be added
+.15%2A600+=+90+ ml of alcohol in 15% solution
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+%28+x+%2B+90+%29+%2F+%28+x+%2B+600+%29+=+.25+
+x+%2B+90+=+.25%2A%28+x+%2B+600+%29+
+x+%2B+90+=+.25x+%2B+150+
+.75x+=+60+
+x+=+80+
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