Question

how much pure alcohol to be added to 400 ml of a solution 15 % to strength 32%

Answer 1

Answer:

Step-by-step explanation:

Let x ml of pure alcohol is to be added.

Then,

Amount of alcohol becomes 60 + x

Total amount of solution becomes 400 + x

60+x/400+x * 100=32

60+x=128+0.32x

0.68x=68

x=100ml