Question

how much pure alcohol to be added to 400 ml of a solution of 15% to strength 32% ?

Answer 1

Given that,

Solution = 400ml

Strength = 32%

Let x ml of alcohol be added.

We need to Calculate the quantity of alcohol

Using formula of quantity

Quantity of alcohol in 400 ml solution

Q = 15 x 400

100

Q = 60 ml

We need to calculate the value x

Using formula for strength

60 + x = 32

400 + x 100

100(60 + x ) = 32( 400 + x )

6000 + 100x = 12800 + 32x

100x - 32x = 12800 - 6000

68x = 6800

x = 6800

68

x = 100 ml

Hence, 100 ml pure alcohol be added.

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