Question

how much pure liquid be added to 400 ml of a 15% solution to make it strength 32% ?

Answer 1

hii mate !!

here's all given that ,

$(400)(.15) = 60ml \: of \: pure \: liquid$
=》
$.32 = \frac{60 + x}{400 + x}$

=》
$.32(400 + x) = 60 + x$
=》128 +.32x = 60+x


$.60 = .68x$
$x = 100$

$hope \: it \: helps$



$be \: brainly$

Answer 2

Hey! ! !

☆ Solution :-

☆ Here's how I did it:

=>(400)(.15)=60

=>(400)(.15)=60 mL of Alcohol

.32=60+x400+x.32=60+x400+x

(.32)(400+x)=60+x(.32)(400+x)=60+x

128+.32x=60+x128+.32x=60+x

68=.68x68=.68x

:- x=100

☆ ☆ ☆ Hop its helpful ☆ ☆ ☆

☆ Regards :- ♡♡《 Nitish kr singh 》♡♡