Question

How much quantity of 80% pure CaCO3 on heating gives 14g CaO?

Answer 1

Answer:

Question:-

Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of CO 2

will be obtained at STP by thermal decomposition of 50 g of CaCO3

Explanation:

Answer:-

Chemical reaction involved is:

CaCO

3

→CaO+CO

2

Molar mass of CaCO

3

=40+12+16×3=100 g

According to the balanced reaction 100 g of CaCO

3

produces 1 mol of CO

2

i.e. 22.4 L at STP.

∴50 g CaCO

3

will produce

100

22.4

×50=11.2 L CO

2

at STP.