How much quantity of heat is
required?m = 120 litrest t1 = 20°C t2 =85°CS = 4.20 = КЛ | *
A: 32750 KJ
B: 32760 KJ
1) C:32770 KJ
C):32780 KJ
Answers
Answered by
0
Answer:
c
Explanation:
I think I hope it helps...
Answered by
3
Answer:
A maybe correct answer
not sure
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