Question

how much quantity of heat is required to raise the temperature of 300 gram of copper (sp.heat 0.909cal gram )from 25°c to 75°c in kcsl?

Answer 1

Answer:

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Step-by-step explanation:

$to \: find : \\ amount \: of \: heat \: (Q) \\ \\ given : \\ mass \: of \: copper \: (m) = 300 \: gm \\ \\ specific \: heat \: capacity \: of \: copper \\ (c) = 0.909 \: \: cal \: /g \\ \\ difference \: in \: temperature \\ Δt = (75 - 25) = 50 \: °C$

$so \: we \: know \: that \\ \\ Q = m \times c \times Δt \\ \\ = 300 \times 50 \times 0.909 \\ \\ = 45.45 \times 300 \\ \\ Q= 13635 \: J$