Chemistry, asked by Askme005, 10 months ago

How much quantity of metallic zinc will have to be reacted with dil. HCI to produce sufficient
hydrogen to completely react with the oxygen obtained by decomposing 5.104 g of potassium
chlorate ? [Zn = 65.3; K= 39 ; Cl = 35.5)
(Ans. 8.1625 g Zn]​
Please help me to solve this!

Answers

Answered by sankarinava30
4

Answer:

plzz support me mares

Explanation:

nswer :

8.124gZn

Solution :

1.0 mole of KClO3≡3.0 mole of Zn

5.104122.5 mole KClO3=3×5.104122.5

mol of Zn=3×5.104×65122.5=8.124 g Zn

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