Chemistry, asked by Askme005, 8 months ago

How much quantity of metallic zinc will have to be reacted with dil. HCI to produce sufficient
hydrogen to completely react with the oxygen obtained by decomposing 5.104 g of potassium
chlorate ? [Zn = 65.3; K= 39 ; Cl = 35.5)
(Ans. 8.1625 g Zn]
Please help me to solve this!

Answers

Answered by sankarinava30

4

Answer:

plzz support me mares

Explanation:

nswer :

8.124gZn

Solution :

1.0 mole of KClO3≡3.0 mole of Zn

5.104122.5 mole KClO3=3×5.104122.5

mol of Zn=3×5.104×65122.5=8.124 g Zn

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