How much quantity of metallic zinc will have to be reacted with dil. HCI to produce sufficient
hydrogen to completely react with the oxygen obtained by decomposing 5.104 g of potassium
chlorate ? [Zn = 65.3; K= 39 ; Cl = 35.5)
(Ans. 8.1625 g Zn]
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Answer:
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Explanation:
nswer :
8.124gZn
Solution :
1.0 mole of KClO3≡3.0 mole of Zn
5.104122.5 mole KClO3=3×5.104122.5
mol of Zn=3×5.104×65122.5=8.124 g Zn
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