Science, asked by singhsuruchi813, 10 months ago

How much quantity of zn will have to be reacted with excess of dilute HCL solution to produce sufficient hydrogen gas for completely reacting with the O2 obtained by decomposing 5.104g of kclo3

Answers

Answered by dckm827

0

Answer:

Explanation:

8.124gZn

Solution :

1.0 mole of KClO3≡3.0 mole of Zn

5.104122.5 mole KClO3=3×5.104122.5

mol of Zn=3×5.104×65122.5=8.124 g Zn

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