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How much quik lime is obtained from 25 g of calcium carbonate

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Answered by adityajadhav192005

Answer:

14 g

SOLUTION

The reaction is .

$CaCO_3 \rightarrow CaO+CO_2$

One mole of calcium carbonate on decomposition gives one mole of calcium oxide.

The molecular weight of calcium carbonate and calcium oxide are 100 g/mol and 56g/mol respectively.

The decomposition of 100 g of calcium carbonate will give 56 g of calcium oxide.

Hence, the decomposition of 25 g of calcium carbonate will give 14 g of calcium oxide (quicklime).

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Answered by Anonymous

Explanation:

The numbers written in front of the compounds in a balanced reaction. Hence, 12 grams of CaO(Quicklime) is obtained from 25 grams of CaCO3 $<body aquacolor=b>$ $\large\orange{}$ $<font color=Red>$ $<marquee>☺️☺️☺️☺️☺️☺️☺️$ $<marquee>☺hi Gurjari here☺️❤️❤️Mark as brianliest✔️❤️❤️☺️☺️☺️☺️☺️☺️☺️$

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How much quik lime is obtained from 25 g of calcium carbonate