Math, asked by ujjwalmcmn, 1 month ago

how much rent did a company pay by hiring a triangular side wall of for 4 months whose area is 800 M² the rate of rent is rupees 510 per square m per year for the wall​

Answers

Answered by Anupk3724
2

Answer:

Given: Dimensions of the triangular sides of walls.

By using Heron’s formula, we can calculate the area of triangle.

Heron's formula for the area of a triangle is: Area = √s(s - a)(s - b)(s - c)

Where a, b and c are the sides of the triangle, and s = Semi-perimeter = Half the Perimeter of the triangle

Triangular sides of walls are, a = 122 m, b = 22 m, c = 120 m

Semi Perimeter, s = (a + b + c)/2

= (122 + 22 + 120)/2

= 264/2

= 132 m

By using Heron’s formula,

Area of a triangle = √s(s - a)(s - b)(s - c)

Substuting the values in order to find area of triangular wall,

= √132(132 - 122) (132 - 22) (132 - 120)

= √132 × 10 × 110 × 12

= 1320 m

Rent of 1 m2 area per year = ₹ 5000

Rent of 1 m2 area per month = ₹ 5000/12

Rent of 1320 m2 area for 3 months = ₹ (5000/12) × 3 × 1320

= ₹ 1650000

Therefore, the company paid ₹ 16,50,000 as rent.

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