Question

How much repulsion is there between two electrons placed 1 cm away from each other .given that mass of electron is 9.1
kg

Answer 1

Given :

Separation between the two electrons =1 cm

To Find :

Repulsion between these two electrons = ?

Solution :

The repulsion between these two electrons is due to the repulsive force between these two electrons which is equal to the electrostatic force  acting between them .

Since the two electrons have negative charge of same magnitude , so they will repel each other .

Now , the electrostatic force between them will be given as :

$F = \frac{1}{4\pi \epsilon_0}\times \frac{Q_1 Q_2}{R^2}$

Or , $F = \frac{9 \times 10^9\times 1.6 \times 10^{-19}\times 1.6 \times 10^{-19}}{(\frac{1}{100})^2}$

Or, $F = 9 \times 10^9 \times 2.56 \times 10^{-38}\times 10^4$

Or, $F = 23 .04 \times 10^{-35} N$

Hence , the repulsive force between these two electrons placed 1 cm away from each other is $F = 23 .04 \times 10^{-35} N$