Question

How much shorter is to walk diagonally across a rectangular field 24 cm long and 18 cm wide than along two of its adjecent sides

Answer 1

Diagonal is 30 cm

Step-by-step explanation:

If ABCD is a rectangle CB is diognal

then we take ABC is right angle triangle

Diognal = hypotenuse

so, BCsqure=ABsqure+ACsqure

Length (AB)=24cm

Breadth(AC)=18cm

Diognal =24squre+18squre

BCsqure=576+324

BCsqure=900

BC=30

Answer 2

SOLUTION:-

As we know that all the four angles of the rectangle are equal to 90°. Then the diagonal along with two sides will form a right angle triangle.

Using Pythagoras Theorem Method;

(Hypotenuse)²=(Base)²+(perpendicular)²

•Perpendicular= 18cm

•Base= 24cm

Therefore,

=) H²= 24² + 18²

=) H²= 576+ 324

=) H²= 900

=) H= √900

=) H= 30cm

If he had to walk on the adjacent side of the rectangular field, then we travel a distance of (24cm + 18cm)= 42cm &

If he walk on the diagonal of the rectangular field we will travel=30cm.

Shorter he walk;

(42cm - 30cm)

=) 12cm

Hope it helps ☺️