how much should a+2b-3c be increased to get 3a
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Answered by
52
let a + 2b-3c be increased by x
so we get
a+2b-3c+x=3a
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.
.
=> x=3a-(a+2b-3c)
=> x=3a-a-2b+3c
=> x=2a-2b+3c
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.
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hence a+2b-3c should be increased 2a-2b+3c times to get 3a
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.
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verification
a+2b-3c+2a-2b+3c
=a+2a+2b-2b+3c-3c
=3a+0+0
=3a
hence proved
so we get
a+2b-3c+x=3a
.
.
.
=> x=3a-(a+2b-3c)
=> x=3a-a-2b+3c
=> x=2a-2b+3c
.
.
.
hence a+2b-3c should be increased 2a-2b+3c times to get 3a
.
.
.
verification
a+2b-3c+2a-2b+3c
=a+2a+2b-2b+3c-3c
=3a+0+0
=3a
hence proved
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