Question

how much should be added to 159.8 3 to 150​

Answer 1

Step-by-step explanation:

159.3-150 = 9.83

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Answer 2

Answer:

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Step-by-step explanation:

The iron oxide has 69.9% iron and 30.1% dioxygen by mass.

Thus, 100 g of iron oxide contains 69.9 g iron and 30.1 g dioxygen.

The number of moles of iron present in 100 g of iron oxide are

$\frac{69.9}{55.8} = 1.25.$

The number of moles of dioxygen present in 100 g of iron oxide are

$\frac{30.1}{32} = 0.94.$

The ratio of the number of oxygen atoms to the number of carbon atoms present in one formula unit of iron oxide is

$\frac{2 \times 0.94}{25} = 1.5$

: 1 = 3 : 2

Hence, the formula of the iron oxide is

Fe²O³