Question

How much should be added to 8y3 – 3y - 4 to get y2 + y +1​

Answer 1

Answer: add -8y3+y2+4y+5

Step-by-step explanation:

if we add

$8y^{3}-3y-4 + (-8y^{3}+y^{2}+4y+5)\\\\8y^{3}-3y-4 -8y^{3}+y^{2}+4y+5)\\\\= y^{2}+y+1$

Answer 2

$let \: x \: be \: \: added$

$x + 8 {y}^{3} - 3y - 4 = {y}^{2} + y + 1$

$x = {y}^{2} + y + 1 - (8 {y}^{3} - 3y - 4)$

$= {y}^{2} + y - 1 - 8 {y}^{3} + 3y + 4$

$= - 8 {y}^{3} + {y}^{2} + 4y + 3$