Question

How much should be subtracted from 3ab-4bc + abc to get 2 ab +3abc +1?
Ans:ab-4bc-2abc-1
plez I need the explanation, the answer can be in any order✨✨✨​

Answer 1

Step-by-step explanation:

3a(a+b+c)−2b(a+b+c)

⇒3a(a+b+c)−2b(a+b+c)=3a

2

+3ab+3ac−(2ab+2b

2

+2bc)

⇒3a(a+b+c)−2b(a+b+c)=3a

2

+3ab+3ac−2ab−2b

2

−2bc

⇒3a(a+b+c)−2b(a+b+c)=3a

2

−2b

2

+ab+3ac−2bc

Required difference ⇒4c(−a+b+c)−(3a

2

−2b

2

+ab+3ac−2bc)

⇒4c(−a+b+c)−(3a

2

−2b

2

+ab+3ac−2bc)=−4ac+4bc+4c

2

−3a

2

+2b

2

−ab−3ac+2bc

⇒4c(−a+b+c)−(3a

2

−2b

2

+ab+3ac−2bc)=−3a

2

+2b

2

+4c

2

−7ac+6bc−ab

Answer 2

Step-by-step explanation:

substract 2ab+3abc-1 from 3ab-4bc+ab

u wiil get right ans.