How much should the pressure be increased in order to decrease the volume by 5% at constant temperature
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as temperature remains constant we can apply Boyle’s Law,
the law can be usefully expressed as P₁V₁ = P₂V₂.
V₂ =0.95 V₁ (as V₂ is 5% less than V₁)
P₁×V₁ = P₂×V₂
P₁×V₁ = P₂ (0.95×V₁)
P₂ = P₁/ 0.95
P₂ = 1.052 P₁


% Increase in pressure = 5.2
16.8k Views ·
the law can be usefully expressed as P₁V₁ = P₂V₂.
V₂ =0.95 V₁ (as V₂ is 5% less than V₁)
P₁×V₁ = P₂×V₂
P₁×V₁ = P₂ (0.95×V₁)
P₂ = P₁/ 0.95
P₂ = 1.052 P₁


% Increase in pressure = 5.2
16.8k Views ·
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