Math, asked by ƒaiŗƴ, 7 months ago

How much silver is need to prepare 1.08 grams of silver nitrate.

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Answers

Answered by Anonymous
31

From the table above, we can see that 1 Mole of Silver Nitrate weighs about 169.87 grams. You can then say that the Formula Weight of Silver Nitrate is 169.87 grams. Note: The terms: Formula Weight and Molecular Weight are the same thing.❤

Answered by dawoodbilal1234587
3

Answer:

169.87 gram silver is needed to prepare 1.08 grams of silver nitrate.

Step-by-step explanation:

hope so it will help you

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