How much so2 is produced by burning sulphur in 0.5 moles of oxygen?
Answers
Answered by
14
Equation for the reaction :
S (s) + O₂(g) — > SO₂ (g)
The mole ratio is 1 : 1
Thus moles of SO₂ produced = 0.5moles.
Molar mass of SO₂ is :
32 + 32 = 64g / mol
Mass of SO₂ produced is :
64 × 0.5 = 32g
S (s) + O₂(g) — > SO₂ (g)
The mole ratio is 1 : 1
Thus moles of SO₂ produced = 0.5moles.
Molar mass of SO₂ is :
32 + 32 = 64g / mol
Mass of SO₂ produced is :
64 × 0.5 = 32g
Answered by
8
Answer:
Explanation:
Equation for the reaction :
S (s) + O₂(g) — > SO₂ (g)
The mole ratio is 1 : 1
Thus moles of SO₂ produced = 0.5moles.
Molar mass of SO₂ is :
32 + 32 = 64g / mol
Mass of SO₂ produced is :
64 × 0.5 = 32g
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