How much sodium fluoride is in a 221g tube of toothpaste that has 0.24% NaF?
Answers
Answer:
Sodium fluoride has a molecular weight of 42
MW Na (23) + F (19) = 42
NaF in toothpaste is 0.243% weight/volume of NaF (read the toothpaste tube)
Convert % NaF to mg/g of NaF compound multiply by 10 = 0.243 x 10 = 2.43 mg NaF/g
Convert mg/g NaF to mg/g F ion divide by 2.2 = 2.43/2.2 = 1.1 mg/g F ion
Convert mg/g F ion to ppm multiply by 1000 = 1.1 x 1000 = 1100 ppm F ion
A pea-sized amount of toothpaste on your brush is roughly 0.4 grams of toothpaste so it contains 0.4 x 2.43 = 0.972 mg NaF or 0.88 mg F ion
A 1 cm (0.4 inches) amount of toothpaste on your brush is approximately 0.8 grams of toothpaste.
A 2 cm length = 1.7g
A 3 cm length = 2.5 g
A tube of toothpaste is 100 ml = 100 g
You do the rest of the math
Explanation:
hope helpful
mark as brainliest
follow me
Explanation:
hope you have understood
