how much steel was actually used, if 1/12 of the steel actually used was wasted in making the tank
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Answer:
Step-by-step explanation:
Given:h=4.5m,r=2.1m
Total surface area of tank=2πr(r+h)
=2×
7
22
×2.1×(2.1+4.5)
=2×
7
22
×2.1×6.6=87.12m
2
Let amount of steel used in making the tank x
Steel wasted=
12
x
Given that: Amount of steel required−Amount of steel wasted=TSA of tank.
⇒x−
12
x
=87.12
⇒
12
11x
=87.12
⇒x=
11
12
×87.12=95.04m 2
∴,95.04m2
steel was used in actual while making such a tank.
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