Question

how much steel was actually used, if 1/12 of the steel actually used was wasted in making the tank​

Answer 1

Answer:

Step-by-step explanation:

Given:h=4.5m,r=2.1m

Total surface area of tank=2πr(r+h)

=2×  

7

22

​  

×2.1×(2.1+4.5)

=2×  

7

22

​  

×2.1×6.6=87.12m  

2

 

Let amount of steel used in making the tank x

Steel wasted=  

12

x

​  

 

Given that: Amount of steel required−Amount of steel wasted=TSA of tank.

⇒x−  

12

x

​  

=87.12

⇒  

12

11x

​  

=87.12

⇒x=  

11

12

​  

×87.12=95.04m 2

 

∴,95.04m2

 steel was used in actual while making such a tank.