Question

how much strain is developed in an iron rod of 1 metre length gets elongated by 1 cm, if a force of 100 kg is applied in one end?​

Answer 1

Answer

-------------

Given that,

Radius r=10mm

Length l=1.0m

Force F=100kN

Young modulus Y=2.0×10

11

Nm

2

Now, the stress is

Stress =

3.14×10

2

m

2

100×10

3

N

=3.18×10

8

Nm

−2

Now, the elongation is

ΔL=

AY

FL

ΔL=

2.0×10

11

3.18×10

8

×1

ΔL=1.59×10

−3

m

ΔL=1.59mm

Now, the strain is

Strain

=

L

ΔL

=

1.0

1.59×10

−3

=1.59×10

−3

Hence, this is the required solution.

Explanation

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